Base | Representation |
---|---|
bin | 100000100011010000100010… |
… | …000011001001100110111011 |
3 | 200202220000001220020011212201 |
4 | 200203100202003021212323 |
5 | 122231020020304131103 |
6 | 1224250553424451031 |
7 | 42103666456645162 |
oct | 4043204203114673 |
9 | 622800056204781 |
10 | 143160421161403 |
11 | 41684aa2619958 |
12 | 14081547479a77 |
13 | 61b5c7b81a739 |
14 | 274d003a0a3d9 |
15 | 1183de766151d |
hex | 8234220c99bb |
143160421161403 has 2 divisors, whose sum is σ = 143160421161404. Its totient is φ = 143160421161402.
The previous prime is 143160421161323. The next prime is 143160421161437. The reversal of 143160421161403 is 304161124061341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143160421161403 - 217 = 143160421030331 is a prime.
It is a super-2 number, since 2×1431604211614032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (143160421141403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71580210580701 + 71580210580702.
It is an arithmetic number, because the mean of its divisors is an integer number (71580210580702).
Almost surely, 2143160421161403 is an apocalyptic number.
143160421161403 is a deficient number, since it is larger than the sum of its proper divisors (1).
143160421161403 is an equidigital number, since it uses as much as digits as its factorization.
143160421161403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 41472, while the sum is 37.
The spelling of 143160421161403 in words is "one hundred forty-three trillion, one hundred sixty billion, four hundred twenty-one million, one hundred sixty-one thousand, four hundred three".
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