Base | Representation |
---|---|
bin | 1101000001010101001010… |
… | …0111011010001000100111 |
3 | 1212200122102100012112111022 |
4 | 3100111102213122020213 |
5 | 3334030204041404233 |
6 | 50240525335001355 |
7 | 3005222341436402 |
oct | 320252247321047 |
9 | 55618370175438 |
10 | 14316512059943 |
11 | 461a664910a15 |
12 | 1732776b0925b |
13 | 7cb06c954212 |
14 | 376ccc556d39 |
15 | 19c612eee398 |
hex | d05529da227 |
14316512059943 has 4 divisors (see below), whose sum is σ = 14325454292688. Its totient is φ = 14307569827200.
The previous prime is 14316512059939. The next prime is 14316512059957. The reversal of 14316512059943 is 34995021561341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14316512059943 - 22 = 14316512059939 is a prime.
It is a super-2 number, since 2×143165120599432 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14316512059643) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4471113971 + ... + 4471117172.
It is an arithmetic number, because the mean of its divisors is an integer number (3581363573172).
Almost surely, 214316512059943 is an apocalyptic number.
14316512059943 is a deficient number, since it is larger than the sum of its proper divisors (8942232745).
14316512059943 is an equidigital number, since it uses as much as digits as its factorization.
14316512059943 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8942232744.
The product of its (nonzero) digits is 3499200, while the sum is 53.
The spelling of 14316512059943 in words is "fourteen trillion, three hundred sixteen billion, five hundred twelve million, fifty-nine thousand, nine hundred forty-three".
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