Base | Representation |
---|---|
bin | 1000010101010101010… |
… | …1010001100111111101 |
3 | 111200112110021001112211 |
4 | 2011111111101213331 |
5 | 4321200340430331 |
6 | 145434102500421 |
7 | 13225530123055 |
oct | 2052525214775 |
9 | 450473231484 |
10 | 143165561341 |
11 | 55797255240 |
12 | 238b5a34711 |
13 | 1066766340a |
14 | 6d01c10565 |
15 | 3acdaba8b1 |
hex | 21555519fd |
143165561341 has 16 divisors (see below), whose sum is σ = 158534722368. Its totient is φ = 128189318400.
The previous prime is 143165561339. The next prime is 143165561369.
It is a happy number.
143165561341 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 143165561341 - 21 = 143165561339 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143165561294 and 143165561303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143165561321) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8703861 + ... + 8720293.
It is an arithmetic number, because the mean of its divisors is an integer number (9908420148).
Almost surely, 2143165561341 is an apocalyptic number.
143165561341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
143165561341 is a deficient number, since it is larger than the sum of its proper divisors (15369161027).
143165561341 is a wasteful number, since it uses less digits than its factorization.
143165561341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28332.
The product of its digits is 129600, while the sum is 40.
The spelling of 143165561341 in words is "one hundred forty-three billion, one hundred sixty-five million, five hundred sixty-one thousand, three hundred forty-one".
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