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143200244003 is a prime number
BaseRepresentation
bin1000010101011101100…
…1100101000100100011
3111200121212112010012212
42011113121211010203
54321233230302003
6145441342112335
713226430663515
oct2052731450443
9450555463185
10143200244003
11558048938a3
122390557b6ab
13106718b78bb
146d0667bbb5
153ad1b6bdd8
hex2157665123

143200244003 has 2 divisors, whose sum is σ = 143200244004. Its totient is φ = 143200244002.

The previous prime is 143200243981. The next prime is 143200244017. The reversal of 143200244003 is 300442002341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143200244003 - 26 = 143200243939 is a prime.

It is a super-3 number, since 3×1432002440033 (a number of 34 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 143200244003.

It is not a weakly prime, because it can be changed into another prime (143200244023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71600122001 + 71600122002.

It is an arithmetic number, because the mean of its divisors is an integer number (71600122002).

Almost surely, 2143200244003 is an apocalyptic number.

143200244003 is a deficient number, since it is larger than the sum of its proper divisors (1).

143200244003 is an equidigital number, since it uses as much as digits as its factorization.

143200244003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 23.

Adding to 143200244003 its reverse (300442002341), we get a palindrome (443642246344).

The spelling of 143200244003 in words is "one hundred forty-three billion, two hundred million, two hundred forty-four thousand, three".