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143200334131 = 1994331661893
BaseRepresentation
bin1000010101011101100…
…1111011000100110011
3111200121212200200211221
42011113121323010303
54321233241143011
6145441344045511
713226431520341
oct2052731730463
9450555620757
10143200334131
1155804945588
1223905603897
131067191992a
146d066a2991
153ad1b88971
hex215767b133

143200334131 has 8 divisors (see below), whose sum is σ = 144252399200. Its totient is φ = 142151594112.

The previous prime is 143200334117. The next prime is 143200334143. The reversal of 143200334131 is 131433002341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143200334131 - 229 = 142663463219 is a prime.

It is a super-2 number, since 2×1432003341312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143200334096 and 143200334105.

It is not an unprimeable number, because it can be changed into a prime (143200334111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 744780 + ... + 917113.

It is an arithmetic number, because the mean of its divisors is an integer number (18031549900).

Almost surely, 2143200334131 is an apocalyptic number.

143200334131 is a deficient number, since it is larger than the sum of its proper divisors (1052065069).

143200334131 is a wasteful number, since it uses less digits than its factorization.

143200334131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1662525.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 143200334131 its reverse (131433002341), we get a palindrome (274633336472).

The spelling of 143200334131 in words is "one hundred forty-three billion, two hundred million, three hundred thirty-four thousand, one hundred thirty-one".

Divisors: 1 199 433 86167 1661893 330716707 719599669 143200334131