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1432012120013 = 4730468342979
BaseRepresentation
bin10100110101101010100…
…100101101111111001101
312001220021101102222121102
4110311222210231333031
5141430230100320023
63013505101312445
7205313411120006
oct24655244557715
95056241388542
101432012120013
11502349566922
121b1649b65725
13a5065acab17
144d449d861ad
15273b3742628
hex14d6a92dfcd

1432012120013 has 4 divisors (see below), whose sum is σ = 1462480463040. Its totient is φ = 1401543776988.

The previous prime is 1432012120009. The next prime is 1432012120073. The reversal of 1432012120013 is 3100212102341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1432012120013 - 22 = 1432012120009 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1432012120073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15234171443 + ... + 15234171536.

It is an arithmetic number, because the mean of its divisors is an integer number (365620115760).

Almost surely, 21432012120013 is an apocalyptic number.

It is an amenable number.

1432012120013 is a deficient number, since it is larger than the sum of its proper divisors (30468343027).

1432012120013 is an equidigital number, since it uses as much as digits as its factorization.

1432012120013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30468343026.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1432012120013 its reverse (3100212102341), we get a palindrome (4532224222354).

The spelling of 1432012120013 in words is "one trillion, four hundred thirty-two billion, twelve million, one hundred twenty thousand, thirteen".

Divisors: 1 47 30468342979 1432012120013