Base | Representation |
---|---|
bin | 1101000001100011011001… |
… | …1100100100100011110011 |
3 | 1212201000021201122202122211 |
4 | 3100120312130210203303 |
5 | 3334111021103034212 |
6 | 50242400521312551 |
7 | 3005416144133002 |
oct | 320306634444363 |
9 | 55630251582584 |
10 | 14320334424307 |
11 | 46212464a792a |
12 | 1733463035757 |
13 | 7cb52b81bc92 |
14 | 37717206ac39 |
15 | 19c7888869a7 |
hex | d06367248f3 |
14320334424307 has 2 divisors, whose sum is σ = 14320334424308. Its totient is φ = 14320334424306.
The previous prime is 14320334424301. The next prime is 14320334424311. The reversal of 14320334424307 is 70342443302341.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14320334424307 is a prime.
It is a super-2 number, since 2×143203344243072 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 14320334424307.
It is not a weakly prime, because it can be changed into another prime (14320334424301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7160167212153 + 7160167212154.
It is an arithmetic number, because the mean of its divisors is an integer number (7160167212154).
Almost surely, 214320334424307 is an apocalyptic number.
14320334424307 is a deficient number, since it is larger than the sum of its proper divisors (1).
14320334424307 is an equidigital number, since it uses as much as digits as its factorization.
14320334424307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 580608, while the sum is 40.
Adding to 14320334424307 its reverse (70342443302341), we get a palindrome (84662777726648).
The spelling of 14320334424307 in words is "fourteen trillion, three hundred twenty billion, three hundred thirty-four million, four hundred twenty-four thousand, three hundred seven".
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