Base | Representation |
---|---|
bin | 11010101011000111… |
… | …10000110001000011 |
3 | 1100222000020122111021 |
4 | 31111203300301003 |
5 | 213312001340120 |
6 | 10324554330311 |
7 | 1014604611331 |
oct | 152543606103 |
9 | 40860218437 |
10 | 14320340035 |
11 | 6089505471 |
12 | 2937a29997 |
13 | 1472aabab1 |
14 | 99bc62b51 |
15 | 58c30daaa |
hex | 3558f0c43 |
14320340035 has 16 divisors (see below), whose sum is σ = 17525367360. Its totient is φ = 11229379200.
The previous prime is 14320339991. The next prime is 14320340051. The reversal of 14320340035 is 53004302341.
It is not a de Polignac number, because 14320340035 - 27 = 14320339907 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14320339991 and 14320340009.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 258010 + ... + 308560.
It is an arithmetic number, because the mean of its divisors is an integer number (1095335460).
Almost surely, 214320340035 is an apocalyptic number.
14320340035 is a deficient number, since it is larger than the sum of its proper divisors (3205027325).
14320340035 is a wasteful number, since it uses less digits than its factorization.
14320340035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51678.
The product of its (nonzero) digits is 4320, while the sum is 25.
Adding to 14320340035 its reverse (53004302341), we get a palindrome (67324642376).
The spelling of 14320340035 in words is "fourteen billion, three hundred twenty million, three hundred forty thousand, thirty-five".
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