14320431113 has 2 divisors, whose sum is σ = 14320431114. Its totient is φ = 14320431112.

The previous prime is 14320431107. The next prime is 14320431131. The reversal of 14320431113 is 31113402341.

Together with next prime (14320431131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14295310969 + 25120144 = 119563^2 + 5012^2 .

It is a cyclic number.

It is not a de Polignac number, because 14320431113 - 2⁸ = 14320430857 is a prime.

It is not a weakly prime, because it can be changed into another prime (14320431133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7160215556 + 7160215557.

It is an arithmetic number, because the mean of its divisors is an integer number (7160215557).

Almost surely, 2^14320431113 is an apocalyptic number.

It is an amenable number.

14320431113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14320431113 is an equidigital number, since it uses as much as digits as its factorization.

14320431113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 14320431113 its reverse (31113402341), we get a palindrome (45433833454).

The spelling of 14320431113 in words is "fourteen billion, three hundred twenty million, four hundred thirty-one thousand, one hundred thirteen".