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143204434006433 is a prime number
BaseRepresentation
bin100000100011111001100001…
…011010110101000110100001
3200210001012200020011100220012
4200203321201122311012201
5122232230140101201213
61224323113032454305
742110115241651502
oct4043714132650641
9623035606140805
10143204434006433
11416a1728734848
1214089b8b24a395
1361ba17406b1c7
1427511bb112ba9
1511851215a94a8
hex823e616b51a1

143204434006433 has 2 divisors, whose sum is σ = 143204434006434. Its totient is φ = 143204434006432.

The previous prime is 143204434006409. The next prime is 143204434006477. The reversal of 143204434006433 is 334600434402341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131863354013329 + 11341079993104 = 11483177^2 + 3367652^2 .

It is a cyclic number.

It is not a de Polignac number, because 143204434006433 - 244 = 125612247962017 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (143204434066433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71602217003216 + 71602217003217.

It is an arithmetic number, because the mean of its divisors is an integer number (71602217003217).

Almost surely, 2143204434006433 is an apocalyptic number.

It is an amenable number.

143204434006433 is a deficient number, since it is larger than the sum of its proper divisors (1).

143204434006433 is an equidigital number, since it uses as much as digits as its factorization.

143204434006433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 995328, while the sum is 41.

Adding to 143204434006433 its reverse (334600434402341), we get a palindrome (477804868408774).

The spelling of 143204434006433 in words is "one hundred forty-three trillion, two hundred four billion, four hundred thirty-four million, six thousand, four hundred thirty-three".