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143204969881 is a prime number
BaseRepresentation
bin1000010101011110101…
…1100110110110011001
3111200122012102012220101
42011113223212312121
54321240433014011
6145442031255401
713226516105551
oct2052753466631
9450565365811
10143204969881
1155807521486
122390707a561
131067288098c
146d0714c161
153ad22a22c1
hex2157ae6d99

143204969881 has 2 divisors, whose sum is σ = 143204969882. Its totient is φ = 143204969880.

The previous prime is 143204969837. The next prime is 143204969893. The reversal of 143204969881 is 188969402341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115793200656 + 27411769225 = 340284^2 + 165565^2 .

It is an emirp because it is prime and its reverse (188969402341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143204969881 - 211 = 143204967833 is a prime.

It is a super-2 number, since 2×1432049698812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (143204969581) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71602484940 + 71602484941.

It is an arithmetic number, because the mean of its divisors is an integer number (71602484941).

Almost surely, 2143204969881 is an apocalyptic number.

It is an amenable number.

143204969881 is a deficient number, since it is larger than the sum of its proper divisors (1).

143204969881 is an equidigital number, since it uses as much as digits as its factorization.

143204969881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2985984, while the sum is 55.

The spelling of 143204969881 in words is "one hundred forty-three billion, two hundred four million, nine hundred sixty-nine thousand, eight hundred eighty-one".