Base | Representation |
---|---|
bin | 1000010101100000000… |
… | …0000110001100011011 |
3 | 111200122120112002220011 |
4 | 2011120000012030123 |
5 | 4321243321404042 |
6 | 145442342342351 |
7 | 13226612546326 |
oct | 2053000061433 |
9 | 450576462804 |
10 | 143210341147 |
11 | 5580a55aa45 |
12 | 23908a2a9b7 |
13 | 10673a11743 |
14 | 6d07b497bd |
15 | 3ad29b3a17 |
hex | 215800631b |
143210341147 has 2 divisors, whose sum is σ = 143210341148. Its totient is φ = 143210341146.
The previous prime is 143210341139. The next prime is 143210341207. The reversal of 143210341147 is 741143012341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 143210341147 - 23 = 143210341139 is a prime.
It is a super-2 number, since 2×1432103411472 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (143210341247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71605170573 + 71605170574.
It is an arithmetic number, because the mean of its divisors is an integer number (71605170574).
Almost surely, 2143210341147 is an apocalyptic number.
143210341147 is a deficient number, since it is larger than the sum of its proper divisors (1).
143210341147 is an equidigital number, since it uses as much as digits as its factorization.
143210341147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 143210341147 its reverse (741143012341), we get a palindrome (884353353488).
The spelling of 143210341147 in words is "one hundred forty-three billion, two hundred ten million, three hundred forty-one thousand, one hundred forty-seven".
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