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14321044012313 is a prime number
BaseRepresentation
bin1101000001100110000010…
…1111011011110100011001
31212201002010011212120102002
43100121200233123310121
53334113444231343223
650242555150250345
73005442551416463
oct320314057336431
955632104776362
1014321044012313
11462157aaa58a5
1217336207b69b5
137cb61283753c
143771dc3bd133
1519c7caceee28
hexd0660bdbd19

14321044012313 has 2 divisors, whose sum is σ = 14321044012314. Its totient is φ = 14321044012312.

The previous prime is 14321044012291. The next prime is 14321044012343. The reversal of 14321044012313 is 31321044012341.

14321044012313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14258379904729 + 62664107584 = 3776027^2 + 250328^2 .

It is a cyclic number.

It is not a de Polignac number, because 14321044012313 - 212 = 14321044008217 is a prime.

It is not a weakly prime, because it can be changed into another prime (14321044012343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7160522006156 + 7160522006157.

It is an arithmetic number, because the mean of its divisors is an integer number (7160522006157).

Almost surely, 214321044012313 is an apocalyptic number.

It is an amenable number.

14321044012313 is a deficient number, since it is larger than the sum of its proper divisors (1).

14321044012313 is an equidigital number, since it uses as much as digits as its factorization.

14321044012313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 14321044012313 its reverse (31321044012341), we get a palindrome (45642088024654).

The spelling of 14321044012313 in words is "fourteen trillion, three hundred twenty-one billion, forty-four million, twelve thousand, three hundred thirteen".