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14322113121103 = 72071987250329
BaseRepresentation
bin1101000001101010000001…
…1101110000101101001111
31212201011212200120220221221
43100122200131300231033
53334123141424333403
650243253221104211
73005511212612644
oct320324035605517
955634780526857
1014322113121103
114621a79531087
12173387a858067
137cb7531906a8
143772a0399dcb
1519c83ead2dbd
hexd06a0770b4f

14322113121103 has 4 divisors (see below), whose sum is σ = 14324100378640. Its totient is φ = 14320125863568.

The previous prime is 14322113121091. The next prime is 14322113121187. The reversal of 14322113121103 is 30112131122341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14322113121103 - 221 = 14322111023951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14322113124103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 993617958 + ... + 993632371.

It is an arithmetic number, because the mean of its divisors is an integer number (3581025094660).

Almost surely, 214322113121103 is an apocalyptic number.

14322113121103 is a deficient number, since it is larger than the sum of its proper divisors (1987257537).

14322113121103 is an equidigital number, since it uses as much as digits as its factorization.

14322113121103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1987257536.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 14322113121103 its reverse (30112131122341), we get a palindrome (44434244243444).

The spelling of 14322113121103 in words is "fourteen trillion, three hundred twenty-two billion, one hundred thirteen million, one hundred twenty-one thousand, one hundred three".

Divisors: 1 7207 1987250329 14322113121103