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143224440424147 is a prime number
BaseRepresentation
bin100000100100001100001001…
…111001010000011011010011
3200210010010022111202200121001
4200210030021321100123103
5122233042123222033042
61224340222151442431
742111424102465105
oct4044141171203323
9623103274680531
10143224440424147
11416aa164847565
1214091a33386417
1361bc011b81cb4
1427521581c9575
1511858e2b91bb7
hex824309e506d3

143224440424147 has 2 divisors, whose sum is σ = 143224440424148. Its totient is φ = 143224440424146.

The previous prime is 143224440424103. The next prime is 143224440424183. The reversal of 143224440424147 is 741424044422341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 143224440424147 - 235 = 143190080685779 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 143224440424097 and 143224440424106.

It is not a weakly prime, because it can be changed into another prime (143224440424187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71612220212073 + 71612220212074.

It is an arithmetic number, because the mean of its divisors is an integer number (71612220212074).

Almost surely, 2143224440424147 is an apocalyptic number.

143224440424147 is a deficient number, since it is larger than the sum of its proper divisors (1).

143224440424147 is an equidigital number, since it uses as much as digits as its factorization.

143224440424147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2752512, while the sum is 46.

Adding to 143224440424147 its reverse (741424044422341), we get a palindrome (884648484846488).

The spelling of 143224440424147 in words is "one hundred forty-three trillion, two hundred twenty-four billion, four hundred forty million, four hundred twenty-four thousand, one hundred forty-seven".