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14323021001 is a prime number
BaseRepresentation
bin11010101011011011…
…11111010011001001
31100222012021212002022
431111231333103021
5213313143133001
610325132014225
71014636445502
oct152555772311
940865255068
1014323021001
11608aa76743
122938901375
13147350a173
1499c35dba9
1558c68d11b
hex355b7f4c9

14323021001 has 2 divisors, whose sum is σ = 14323021002. Its totient is φ = 14323021000.

The previous prime is 14323020997. The next prime is 14323021007. The reversal of 14323021001 is 10012032341.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9273497401 + 5049523600 = 96299^2 + 71060^2 .

It is an emirp because it is prime and its reverse (10012032341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14323021001 - 22 = 14323020997 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (14323021007) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161510500 + 7161510501.

It is an arithmetic number, because the mean of its divisors is an integer number (7161510501).

Almost surely, 214323021001 is an apocalyptic number.

It is an amenable number.

14323021001 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323021001 is an equidigital number, since it uses as much as digits as its factorization.

14323021001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 14323021001 its reverse (10012032341), we get a palindrome (24335053342).

The spelling of 14323021001 in words is "fourteen billion, three hundred twenty-three million, twenty-one thousand, one".