Base | Representation |
---|---|
bin | 10100110101111100011… |
… | …101001011001011110101 |
3 | 12001221001021222012011010 |
4 | 110311330131023023311 |
5 | 141431333401213331 |
6 | 3013554535502433 |
7 | 205324013150346 |
oct | 24657435131365 |
9 | 5057037865133 |
10 | 1432312132341 |
11 | 5024929495a2 |
12 | 1b1712527a19 |
13 | a50b30013cc |
14 | 4d477b600cd |
15 | 273cec54e46 |
hex | 14d7c74b2f5 |
1432312132341 has 16 divisors (see below), whose sum is σ = 1995163378560. Its totient is φ = 912819835200.
The previous prime is 1432312132327. The next prime is 1432312132367.
1432312132341 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 1432312132341 - 25 = 1432312132309 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1432312132299 and 1432312132308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1432312137341) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 81492985 + ... + 81510558.
It is an arithmetic number, because the mean of its divisors is an integer number (124697711160).
Almost surely, 21432312132341 is an apocalyptic number.
It is an amenable number.
1432312132341 is a deficient number, since it is larger than the sum of its proper divisors (562851246219).
1432312132341 is a wasteful number, since it uses less digits than its factorization.
1432312132341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 163003676.
The product of its digits is 10368, while the sum is 30.
The spelling of 1432312132341 in words is "one trillion, four hundred thirty-two billion, three hundred twelve million, one hundred thirty-two thousand, three hundred forty-one".
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