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14323140512531 is a prime number
BaseRepresentation
bin1101000001101101110110…
…1100111100101100010011
31212201021112021210211001022
43100123131230330230103
53334132242432400111
650243543201430055
73005545526366144
oct320333554745423
955637467724038
1014323140512531
114622456463504
121733b0693b32b
137cb887c9b406
1437735a9d7acb
1519c89edc52db
hexd06ddb3cb13

14323140512531 has 2 divisors, whose sum is σ = 14323140512532. Its totient is φ = 14323140512530.

The previous prime is 14323140512393. The next prime is 14323140512557. The reversal of 14323140512531 is 13521504132341.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14323140512531 - 234 = 14305960643347 is a prime.

It is a super-2 number, since 2×143231405125312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14323140512491 and 14323140512500.

It is not a weakly prime, because it can be changed into another prime (14323140512731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161570256265 + 7161570256266.

It is an arithmetic number, because the mean of its divisors is an integer number (7161570256266).

Almost surely, 214323140512531 is an apocalyptic number.

14323140512531 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323140512531 is an equidigital number, since it uses as much as digits as its factorization.

14323140512531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 14323140512531 its reverse (13521504132341), we get a palindrome (27844644644872).

The spelling of 14323140512531 in words is "fourteen trillion, three hundred twenty-three billion, one hundred forty million, five hundred twelve thousand, five hundred thirty-one".