Base | Representation |
---|---|
bin | 1101000001101110101001… |
… | …1100100111001101000001 |
3 | 1212201022002012011001222121 |
4 | 3100123222130213031001 |
5 | 3334133212202142032 |
6 | 50244020320404241 |
7 | 3005554034010331 |
oct | 320335234471501 |
9 | 55638065131877 |
10 | 14323354334017 |
11 | 4622556126783 |
12 | 1733b66476681 |
13 | 7cb8c03847c1 |
14 | 37737b1770c1 |
15 | 19c8b3a5ea97 |
hex | d06ea727341 |
14323354334017 has 2 divisors, whose sum is σ = 14323354334018. Its totient is φ = 14323354334016.
The previous prime is 14323354333969. The next prime is 14323354334033. The reversal of 14323354334017 is 71043345332341.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13981736294656 + 341618039361 = 3739216^2 + 584481^2 .
It is a cyclic number.
It is not a de Polignac number, because 14323354334017 - 27 = 14323354333889 is a prime.
It is not a weakly prime, because it can be changed into another prime (14333354334017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161677167008 + 7161677167009.
It is an arithmetic number, because the mean of its divisors is an integer number (7161677167009).
Almost surely, 214323354334017 is an apocalyptic number.
It is an amenable number.
14323354334017 is a deficient number, since it is larger than the sum of its proper divisors (1).
14323354334017 is an equidigital number, since it uses as much as digits as its factorization.
14323354334017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1088640, while the sum is 43.
Adding to 14323354334017 its reverse (71043345332341), we get a palindrome (85366699666358).
The spelling of 14323354334017 in words is "fourteen trillion, three hundred twenty-three billion, three hundred fifty-four million, three hundred thirty-four thousand, seventeen".
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