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14323441200953 is a prime number
BaseRepresentation
bin1101000001101110111110…
…0111111110111100111001
31212201022022020121101000112
43100123233213332330321
53334133401421412303
650244033102314105
73005556140243603
oct320335747767471
955638266541015
1014323441200953
1146225a0168135
121733b8b588935
137cb90537a661
1437738890a173
1519c8bb4bd0d8
hexd06ef9fef39

14323441200953 has 2 divisors, whose sum is σ = 14323441200954. Its totient is φ = 14323441200952.

The previous prime is 14323441200883. The next prime is 14323441200961. The reversal of 14323441200953 is 35900214432341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11506186373929 + 2817254827024 = 3392077^2 + 1678468^2 .

It is a cyclic number.

It is not a de Polignac number, because 14323441200953 - 28 = 14323441200697 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14323441200953.

It is not a weakly prime, because it can be changed into another prime (14323441200253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7161720600476 + 7161720600477.

It is an arithmetic number, because the mean of its divisors is an integer number (7161720600477).

Almost surely, 214323441200953 is an apocalyptic number.

It is an amenable number.

14323441200953 is a deficient number, since it is larger than the sum of its proper divisors (1).

14323441200953 is an equidigital number, since it uses as much as digits as its factorization.

14323441200953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 41.

The spelling of 14323441200953 in words is "fourteen trillion, three hundred twenty-three billion, four hundred forty-one million, two hundred thousand, nine hundred fifty-three".