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14324212135369 is a prime number
BaseRepresentation
bin1101000001110001110110…
…0100110111010111001001
31212201101021222020220020001
43100130131210313113021
53334141441301312434
650244241402203001
73005614221133033
oct320343544672711
955641258226201
1014324212135369
114622956356614
1217341657b3461
137cb9c8cc4976
1437741d06ac53
1519c914003114
hexd071d9375c9

14324212135369 has 2 divisors, whose sum is σ = 14324212135370. Its totient is φ = 14324212135368.

The previous prime is 14324212135273. The next prime is 14324212135427. The reversal of 14324212135369 is 96353121242341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11755901401344 + 2568310734025 = 3428688^2 + 1602595^2 .

It is a cyclic number.

It is not a de Polignac number, because 14324212135369 - 223 = 14324203746761 is a prime.

It is a super-4 number, since 4×143242121353694 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (14324212135469) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162106067684 + 7162106067685.

It is an arithmetic number, because the mean of its divisors is an integer number (7162106067685).

Almost surely, 214324212135369 is an apocalyptic number.

It is an amenable number.

14324212135369 is a deficient number, since it is larger than the sum of its proper divisors (1).

14324212135369 is an equidigital number, since it uses as much as digits as its factorization.

14324212135369 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 933120, while the sum is 46.

The spelling of 14324212135369 in words is "fourteen trillion, three hundred twenty-four billion, two hundred twelve million, one hundred thirty-five thousand, three hundred sixty-nine".