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14324232656131 is a prime number
BaseRepresentation
bin1101000001110001111011…
…0011001001010100000011
31212201101100101212110102021
43100130132303021110003
53334142012024444011
650244243414102311
73005614560431236
oct320343663112403
955641311773367
1014324232656131
1146229669a2122
12173417064a997
137cba0032b128
14377421a8d41d
1519c915c08471
hexd071ecc9503

14324232656131 has 2 divisors, whose sum is σ = 14324232656132. Its totient is φ = 14324232656130.

The previous prime is 14324232656033. The next prime is 14324232656207. The reversal of 14324232656131 is 13165623242341.

It is a strong prime.

It is an emirp because it is prime and its reverse (13165623242341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14324232656131 - 243 = 5528139633923 is a prime.

It is a super-2 number, since 2×143242326561312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14324232686131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162116328065 + 7162116328066.

It is an arithmetic number, because the mean of its divisors is an integer number (7162116328066).

Almost surely, 214324232656131 is an apocalyptic number.

14324232656131 is a deficient number, since it is larger than the sum of its proper divisors (1).

14324232656131 is an equidigital number, since it uses as much as digits as its factorization.

14324232656131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 622080, while the sum is 43.

Adding to 14324232656131 its reverse (13165623242341), we get a palindrome (27489855898472).

The spelling of 14324232656131 in words is "fourteen trillion, three hundred twenty-four billion, two hundred thirty-two million, six hundred fifty-six thousand, one hundred thirty-one".