Base | Representation |
---|---|
bin | 1101000001110001111101… |
… | …0110010010100011111011 |
3 | 1212201101101001012112011112 |
4 | 3100130133112102203323 |
5 | 3334142021404302201 |
6 | 50244244343350535 |
7 | 3005615031642122 |
oct | 320343726224373 |
9 | 55641331175145 |
10 | 14324241869051 |
11 | 4622971114a04 |
12 | 173417375244b |
13 | 7cba0220566a |
14 | 377422daaab9 |
15 | 19c9169280bb |
hex | d071f5928fb |
14324241869051 has 2 divisors, whose sum is σ = 14324241869052. Its totient is φ = 14324241869050.
The previous prime is 14324241869039. The next prime is 14324241869081. The reversal of 14324241869051 is 15096814242341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14324241869051 - 238 = 14049363962107 is a prime.
It is not a weakly prime, because it can be changed into another prime (14324241869081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162120934525 + 7162120934526.
It is an arithmetic number, because the mean of its divisors is an integer number (7162120934526).
Almost surely, 214324241869051 is an apocalyptic number.
14324241869051 is a deficient number, since it is larger than the sum of its proper divisors (1).
14324241869051 is an equidigital number, since it uses as much as digits as its factorization.
14324241869051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1658880, while the sum is 50.
The spelling of 14324241869051 in words is "fourteen trillion, three hundred twenty-four billion, two hundred forty-one million, eight hundred sixty-nine thousand, fifty-one".
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