14324242000153 has 2 divisors, whose sum is σ = 14324242000154. Its totient is φ = 14324242000152.

The previous prime is 14324242000069. The next prime is 14324242000181. The reversal of 14324242000153 is 35100024242341.

14324242000153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12013072816144 + 2311169184009 = 3465988^2 + 1520253^2 .

It is a cyclic number.

It is not a de Polignac number, because 14324242000153 - 2¹⁷ = 14324241869081 is a prime.

It is not a weakly prime, because it can be changed into another prime (14324272000153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162121000076 + 7162121000077.

It is an arithmetic number, because the mean of its divisors is an integer number (7162121000077).

Almost surely, 2^{14324242000153} is an apocalyptic number.

It is an amenable number.

14324242000153 is a deficient number, since it is larger than the sum of its proper divisors (1).

14324242000153 is an equidigital number, since it uses as much as digits as its factorization.

14324242000153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 14324242000153 its reverse (35100024242341), we get a palindrome (49424266242494).

The spelling of 14324242000153 in words is "fourteen trillion, three hundred twenty-four billion, two hundred forty-two million, one hundred fifty-three", and thus it is an aban number.