14324401200113 has 2 divisors, whose sum is σ = 14324401200114. Its totient is φ = 14324401200112.

The previous prime is 14324401200089. The next prime is 14324401200149. The reversal of 14324401200113 is 31100210442341.

14324401200113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7349694505024 + 6974706695089 = 2711032^2 + 2640967^2 .

It is a cyclic number.

It is not a de Polignac number, because 14324401200113 - 2¹⁰ = 14324401199089 is a prime.

It is not a weakly prime, because it can be changed into another prime (14324401203113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7162200600056 + 7162200600057.

It is an arithmetic number, because the mean of its divisors is an integer number (7162200600057).

Almost surely, 2^{14324401200113} is an apocalyptic number.

It is an amenable number.

14324401200113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14324401200113 is an equidigital number, since it uses as much as digits as its factorization.

14324401200113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 14324401200113 its reverse (31100210442341), we get a palindrome (45424611642454).

The spelling of 14324401200113 in words is "fourteen trillion, three hundred twenty-four billion, four hundred one million, two hundred thousand, one hundred thirteen".