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143244232202417 is a prime number
BaseRepresentation
bin100000100100011110100101…
…100100111001100010110001
3200210012000101211111012022212
4200210132211210321202301
5122233403141420434132
61224353254122141505
742113024416022423
oct4044364544714261
9623160354435285
10143244232202417
11417075a0788505
1214095837651895
1361c0b473842b8
1427530b498c813
1511861a04cc5b2
hex8247a59398b1

143244232202417 has 2 divisors, whose sum is σ = 143244232202418. Its totient is φ = 143244232202416.

The previous prime is 143244232202339. The next prime is 143244232202431. The reversal of 143244232202417 is 714202232442341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 143020575092641 + 223657109776 = 11959121^2 + 472924^2 .

It is an emirp because it is prime and its reverse (714202232442341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143244232202417 - 212 = 143244232198321 is a prime.

It is not a weakly prime, because it can be changed into another prime (143244232202497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71622116101208 + 71622116101209.

It is an arithmetic number, because the mean of its divisors is an integer number (71622116101209).

Almost surely, 2143244232202417 is an apocalyptic number.

It is an amenable number.

143244232202417 is a deficient number, since it is larger than the sum of its proper divisors (1).

143244232202417 is an equidigital number, since it uses as much as digits as its factorization.

143244232202417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 516096, while the sum is 41.

Adding to 143244232202417 its reverse (714202232442341), we get a palindrome (857446464644758).

The spelling of 143244232202417 in words is "one hundred forty-three trillion, two hundred forty-four billion, two hundred thirty-two million, two hundred two thousand, four hundred seventeen".