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14325025111 = 15217941383
BaseRepresentation
bin11010101011101011…
…01000100101010111
31100222100001200012121
431111311220211113
5213314201300421
610325243000411
71014662463415
oct152565504527
940870050177
1014325025111
116091115431
122939509107
131473a5c427
1499c7222b5
1558c936d41
hex355d68957

14325025111 has 4 divisors (see below), whose sum is σ = 14325981712. Its totient is φ = 14324068512.

The previous prime is 14325025093. The next prime is 14325025123. The reversal of 14325025111 is 11152052341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14325025111 - 27 = 14325024983 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14325025181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455475 + ... + 485908.

It is an arithmetic number, because the mean of its divisors is an integer number (3581495428).

Almost surely, 214325025111 is an apocalyptic number.

14325025111 is a deficient number, since it is larger than the sum of its proper divisors (956601).

14325025111 is an equidigital number, since it uses as much as digits as its factorization.

14325025111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 956600.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 14325025111 its reverse (11152052341), we get a palindrome (25477077452).

The spelling of 14325025111 in words is "fourteen billion, three hundred twenty-five million, twenty-five thousand, one hundred eleven".

Divisors: 1 15217 941383 14325025111