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14325332311 = 16785780433
BaseRepresentation
bin11010101011101101…
…10011100101010111
31100222100122021121101
431111312303211113
5213314241113221
610325253330531
71014665213143
oct152566634527
940870567541
1014325332311
116091305214
122939636a47
131473b391c4
1499c7a2223
1558c997d91
hex355db3957

14325332311 has 4 divisors (see below), whose sum is σ = 14411112912. Its totient is φ = 14239551712.

The previous prime is 14325332257. The next prime is 14325332323. The reversal of 14325332311 is 11323352341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14325332311 - 219 = 14324808023 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14325332311.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14325332381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42890050 + ... + 42890383.

It is an arithmetic number, because the mean of its divisors is an integer number (3602778228).

Almost surely, 214325332311 is an apocalyptic number.

14325332311 is a deficient number, since it is larger than the sum of its proper divisors (85780601).

14325332311 is an equidigital number, since it uses as much as digits as its factorization.

14325332311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85780600.

The product of its digits is 6480, while the sum is 28.

Adding to 14325332311 its reverse (11323352341), we get a palindrome (25648684652).

The spelling of 14325332311 in words is "fourteen billion, three hundred twenty-five million, three hundred thirty-two thousand, three hundred eleven".

Divisors: 1 167 85780433 14325332311