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143304444111 = 31717891570649
BaseRepresentation
bin1000010101110110011…
…1000100100011001111
3111200220010121000220010
42011131213010203033
54321441414202421
6145455543324303
713232134451103
oct2053547044317
9450803530803
10143304444111
1155858693994
1223934450693
131068a36c07a
146d16443903
153adada1076
hex215d9c48cf

143304444111 has 16 divisors (see below), whose sum is σ = 202425372000. Its totient is φ = 89866195968.

The previous prime is 143304444079. The next prime is 143304444119. The reversal of 143304444111 is 111444403341.

143304444111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 143304444111 - 25 = 143304444079 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143304444119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 694086 + ... + 876563.

It is an arithmetic number, because the mean of its divisors is an integer number (12651585750).

Almost surely, 2143304444111 is an apocalyptic number.

143304444111 is a deficient number, since it is larger than the sum of its proper divisors (59120927889).

143304444111 is a wasteful number, since it uses less digits than its factorization.

143304444111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1572458.

The product of its (nonzero) digits is 9216, while the sum is 30.

Adding to 143304444111 its reverse (111444403341), we get a palindrome (254748847452).

The spelling of 143304444111 in words is "one hundred forty-three billion, three hundred four million, four hundred forty-four thousand, one hundred eleven".

Divisors: 1 3 17 51 1789 5367 30413 91239 1570649 4711947 26701033 80103099 2809891061 8429673183 47768148037 143304444111