Base | Representation |
---|---|
bin | 1000010101111000100… |
… | …0110111111000101011 |
3 | 111200220202021012221001 |
4 | 2011132020313320223 |
5 | 4322001201231011 |
6 | 145500501255431 |
7 | 13232302665013 |
oct | 2053610677053 |
9 | 450822235831 |
10 | 143313305131 |
11 | 55862696347 |
12 | 23937404577 |
13 | 1068c152389 |
14 | 6d176acc43 |
15 | 3adba517c1 |
hex | 215e237e2b |
143313305131 has 2 divisors, whose sum is σ = 143313305132. Its totient is φ = 143313305130.
The previous prime is 143313305117. The next prime is 143313305137. The reversal of 143313305131 is 131503313341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143313305131 - 215 = 143313272363 is a prime.
It is a super-2 number, since 2×1433133051312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 143313305131.
It is not a weakly prime, because it can be changed into another prime (143313305137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71656652565 + 71656652566.
It is an arithmetic number, because the mean of its divisors is an integer number (71656652566).
Almost surely, 2143313305131 is an apocalyptic number.
143313305131 is a deficient number, since it is larger than the sum of its proper divisors (1).
143313305131 is an equidigital number, since it uses as much as digits as its factorization.
143313305131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4860, while the sum is 28.
Adding to 143313305131 its reverse (131503313341), we get a palindrome (274816618472).
The spelling of 143313305131 in words is "one hundred forty-three billion, three hundred thirteen million, three hundred five thousand, one hundred thirty-one".
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