Base | Representation |
---|---|
bin | 11010101100011011… |
… | …11110000010010010 |
3 | 1100222210001202222211 |
4 | 31112031332002102 |
5 | 213322314420214 |
6 | 10330031422334 |
7 | 1015100633134 |
oct | 152615760222 |
9 | 40883052884 |
10 | 14331404434 |
11 | 60947822a6 |
12 | 293b6849aa |
13 | 1475183c89 |
14 | 99d503054 |
15 | 58d2970c4 |
hex | 35637e092 |
14331404434 has 4 divisors (see below), whose sum is σ = 21497106654. Its totient is φ = 7165702216.
The previous prime is 14331404401. The next prime is 14331404441. The reversal of 14331404434 is 43440413341.
It is a happy number.
14331404434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 43440413341 = 13 ⋅3341570257.
It can be written as a sum of positive squares in only one way, i.e., 8455722025 + 5875682409 = 91955^2 + 76653^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14331404396 and 14331404405.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3582851107 + ... + 3582851110.
Almost surely, 214331404434 is an apocalyptic number.
14331404434 is a deficient number, since it is larger than the sum of its proper divisors (7165702220).
14331404434 is an equidigital number, since it uses as much as digits as its factorization.
14331404434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7165702219.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 14331404434 its reverse (43440413341), we get a palindrome (57771817775).
The spelling of 14331404434 in words is "fourteen billion, three hundred thirty-one million, four hundred four thousand, four hundred thirty-four".
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