Base | Representation |
---|---|
bin | 10100110110110001011… |
… | …000111011110010010110 |
3 | 12002000100012001100222122 |
4 | 110312301120323302112 |
5 | 141440143223310032 |
6 | 3014223022255542 |
7 | 205355015544245 |
oct | 24666130736226 |
9 | 5060305040878 |
10 | 1433200213142 |
11 | 5028a917a875 |
12 | 1b191ba275b2 |
13 | a51c4cb37c9 |
14 | 4d51da9695c |
15 | 27432bca012 |
hex | 14db163bc96 |
1433200213142 has 4 divisors (see below), whose sum is σ = 2149800319716. Its totient is φ = 716600106570.
The previous prime is 1433200213139. The next prime is 1433200213163. The reversal of 1433200213142 is 2413120023341.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 358300053284 + ... + 358300053287.
It is an arithmetic number, because the mean of its divisors is an integer number (537450079929).
Almost surely, 21433200213142 is an apocalyptic number.
1433200213142 is a deficient number, since it is larger than the sum of its proper divisors (716600106574).
1433200213142 is an equidigital number, since it uses as much as digits as its factorization.
1433200213142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 716600106573.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 1433200213142 its reverse (2413120023341), we get a palindrome (3846320236483).
The spelling of 1433200213142 in words is "one trillion, four hundred thirty-three billion, two hundred million, two hundred thirteen thousand, one hundred forty-two".
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