Base | Representation |
---|---|
bin | 1101000010010000001000… |
… | …0110110111001011001001 |
3 | 1212202011021111120012000010 |
4 | 3100210002012313023021 |
5 | 3334310113323020131 |
6 | 50252104152502133 |
7 | 3006322530202245 |
oct | 320440206671311 |
9 | 55664244505003 |
10 | 14332341220041 |
11 | 4626347a80209 |
12 | 17358540aa949 |
13 | 7cc6c31c2a40 |
14 | 377990937425 |
15 | 19cc3c9eab46 |
hex | d09021b72c9 |
14332341220041 has 64 divisors (see below), whose sum is σ = 20772993040128. Its totient is φ = 8737544798208.
The previous prime is 14332341220031. The next prime is 14332341220063. The reversal of 14332341220041 is 14002214323341.
It is not a de Polignac number, because 14332341220041 - 221 = 14332339122889 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 14332341219990 and 14332341220008.
It is not an unprimeable number, because it can be changed into a prime (14332341220031) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2290605985 + ... + 2290612241.
It is an arithmetic number, because the mean of its divisors is an integer number (324578016252).
Almost surely, 214332341220041 is an apocalyptic number.
It is an amenable number.
14332341220041 is a deficient number, since it is larger than the sum of its proper divisors (6440651820087).
14332341220041 is a wasteful number, since it uses less digits than its factorization.
14332341220041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7690.
The product of its (nonzero) digits is 13824, while the sum is 30.
Adding to 14332341220041 its reverse (14002214323341), we get a palindrome (28334555543382).
The spelling of 14332341220041 in words is "fourteen trillion, three hundred thirty-two billion, three hundred forty-one million, two hundred twenty thousand, forty-one".
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