Base | Representation |
---|---|
bin | 10100110110110011110… |
… | …001110110100110001001 |
3 | 12002000102222110222200212 |
4 | 110312303301312212021 |
5 | 141440234004044123 |
6 | 3014231013410505 |
7 | 205356013353302 |
oct | 24666361664611 |
9 | 5060388428625 |
10 | 1433240299913 |
11 | 50291986a634 |
12 | 1b1931339a35 |
13 | a52003aa9a6 |
14 | 4d52512d7a9 |
15 | 27436497878 |
hex | 14db3c76989 |
1433240299913 has 2 divisors, whose sum is σ = 1433240299914. Its totient is φ = 1433240299912.
The previous prime is 1433240299873. The next prime is 1433240300017. The reversal of 1433240299913 is 3199920423341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 724155046729 + 709085253184 = 850973^2 + 842072^2 .
It is a cyclic number.
It is not a de Polignac number, because 1433240299913 - 214 = 1433240283529 is a prime.
It is not a weakly prime, because it can be changed into another prime (1433240299013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 716620149956 + 716620149957.
It is an arithmetic number, because the mean of its divisors is an integer number (716620149957).
Almost surely, 21433240299913 is an apocalyptic number.
It is an amenable number.
1433240299913 is a deficient number, since it is larger than the sum of its proper divisors (1).
1433240299913 is an equidigital number, since it uses as much as digits as its factorization.
1433240299913 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1259712, while the sum is 50.
The spelling of 1433240299913 in words is "one trillion, four hundred thirty-three billion, two hundred forty million, two hundred ninety-nine thousand, nine hundred thirteen".
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