14332422423341 has 4 divisors (see below), whose sum is σ = 15635369916384. Its totient is φ = 13029474930300.

The previous prime is 14332422423287. The next prime is 14332422423343.

14332422423341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14332422423341 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14332422423295 and 14332422423304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14332422423343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 651473746505 + ... + 651473746526.

It is an arithmetic number, because the mean of its divisors is an integer number (3908842479096).

Almost surely, 2^{14332422423341} is an apocalyptic number.

14332422423341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14332422423341 is a deficient number, since it is larger than the sum of its proper divisors (1302947493043).

14332422423341 is a wasteful number, since it uses less digits than its factorization.

14332422423341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1302947493042.

The product of its digits is 331776, while the sum is 38.

It can be divided in two parts, 1433242 and 2423341, that added together give a palindrome (3856583).

The spelling of 14332422423341 in words is "fourteen trillion, three hundred thirty-two billion, four hundred twenty-two million, four hundred twenty-three thousand, three hundred forty-one".