143340124420043 has 2 divisors, whose sum is σ = 143340124420044. Its totient is φ = 143340124420042.

The previous prime is 143340124420039. The next prime is 143340124420061. The reversal of 143340124420043 is 340024421043341.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 143340124420043 - 2² = 143340124420039 is a prime.

It is a super-4 number, since 4×143340124420043⁴ (a number of 58 digits) contains 4444 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 143340124419985 and 143340124420012.

It is not a weakly prime, because it can be changed into another prime (143340124420013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71670062210021 + 71670062210022.

It is an arithmetic number, because the mean of its divisors is an integer number (71670062210022).

Almost surely, 2^{143340124420043} is an apocalyptic number.

143340124420043 is a deficient number, since it is larger than the sum of its proper divisors (1).

143340124420043 is an equidigital number, since it uses as much as digits as its factorization.

143340124420043 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 143340124420043 its reverse (340024421043341), we get a palindrome (483364545463384).

The spelling of 143340124420043 in words is "one hundred forty-three trillion, three hundred forty billion, one hundred twenty-four million, four hundred twenty thousand, forty-three".