Base | Representation |
---|---|
bin | 1000010101111111101… |
… | …1101011010001110011 |
3 | 111200222211220012101201 |
4 | 2011133323223101303 |
5 | 4322031402300201 |
6 | 145503454312031 |
7 | 13233116540215 |
oct | 2053773532163 |
9 | 450884805351 |
10 | 143343400051 |
11 | 55878681085 |
12 | 239454b8617 |
13 | 1069545b617 |
14 | 6d1b6a45b5 |
15 | 3ade4e8801 |
hex | 215feeb473 |
143343400051 has 2 divisors, whose sum is σ = 143343400052. Its totient is φ = 143343400050.
The previous prime is 143343400033. The next prime is 143343400061. The reversal of 143343400051 is 150004343341.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 143343400051 - 27 = 143343399923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143343399992 and 143343400019.
It is not a weakly prime, because it can be changed into another prime (143343400021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71671700025 + 71671700026.
It is an arithmetic number, because the mean of its divisors is an integer number (71671700026).
Almost surely, 2143343400051 is an apocalyptic number.
143343400051 is a deficient number, since it is larger than the sum of its proper divisors (1).
143343400051 is an equidigital number, since it uses as much as digits as its factorization.
143343400051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8640, while the sum is 28.
Adding to 143343400051 its reverse (150004343341), we get a palindrome (293347743392).
The spelling of 143343400051 in words is "one hundred forty-three billion, three hundred forty-three million, four hundred thousand, fifty-one".
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