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143402211433001 is a prime number
BaseRepresentation
bin100000100110110001101101…
…110111110101101000101001
3200210202010011200021121211002
4200212301231313311220221
5122244000212111324001
61224554022205244345
742130316324231543
oct4046615567655051
9623663150247732
10143402211433001
11417685999586a4
12141003865636b5
136202a02a84171
14275a9bdd5c693
15118a34985346b
hex826c6ddf5a29

143402211433001 has 2 divisors, whose sum is σ = 143402211433002. Its totient is φ = 143402211433000.

The previous prime is 143402211432983. The next prime is 143402211433009. The reversal of 143402211433001 is 100334112204341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86838635625625 + 56563575807376 = 9318725^2 + 7520876^2 .

It is an emirp because it is prime and its reverse (100334112204341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 143402211433001 - 214 = 143402211416617 is a prime.

It is not a weakly prime, because it can be changed into another prime (143402211433009) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71701105716500 + 71701105716501.

It is an arithmetic number, because the mean of its divisors is an integer number (71701105716501).

Almost surely, 2143402211433001 is an apocalyptic number.

It is an amenable number.

143402211433001 is a deficient number, since it is larger than the sum of its proper divisors (1).

143402211433001 is an equidigital number, since it uses as much as digits as its factorization.

143402211433001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 143402211433001 its reverse (100334112204341), we get a palindrome (243736323637342).

The spelling of 143402211433001 in words is "one hundred forty-three trillion, four hundred two billion, two hundred eleven million, four hundred thirty-three thousand, one".