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14340222433 is a prime number
BaseRepresentation
bin11010101101011111…
…00110110111100001
31101000101122210000101
431112233212313201
5213332044104213
610330544422401
71015235610445
oct152657466741
941011583011
1014340222433
1160997553a9
122942617a01
131476c50824
149a075a825
1558de39bdd
hex356be6de1

14340222433 has 2 divisors, whose sum is σ = 14340222434. Its totient is φ = 14340222432.

The previous prime is 14340222401. The next prime is 14340222439. The reversal of 14340222433 is 33422204341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12812428864 + 1527793569 = 113192^2 + 39087^2 .

It is an emirp because it is prime and its reverse (33422204341) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14340222433 - 25 = 14340222401 is a prime.

It is not a weakly prime, because it can be changed into another prime (14340222439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170111216 + 7170111217.

It is an arithmetic number, because the mean of its divisors is an integer number (7170111217).

Almost surely, 214340222433 is an apocalyptic number.

It is an amenable number.

14340222433 is a deficient number, since it is larger than the sum of its proper divisors (1).

14340222433 is an equidigital number, since it uses as much as digits as its factorization.

14340222433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 14340222433 its reverse (33422204341), we get a palindrome (47762426774).

The spelling of 14340222433 in words is "fourteen billion, three hundred forty million, two hundred twenty-two thousand, four hundred thirty-three".