14341112255531 has 4 divisors (see below), whose sum is σ = 14342145565200. Its totient is φ = 14340078945864.

The previous prime is 14341112255527. The next prime is 14341112255557. The reversal of 14341112255531 is 13555221114341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14341112255531 - 2² = 14341112255527 is a prime.

It is a super-2 number, since 2×14341112255531² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14341112255521) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 516634016 + ... + 516661773.

It is an arithmetic number, because the mean of its divisors is an integer number (3585536391300).

Almost surely, 2^{14341112255531} is an apocalyptic number.

14341112255531 is a deficient number, since it is larger than the sum of its proper divisors (1033309669).

14341112255531 is a wasteful number, since it uses less digits than its factorization.

14341112255531 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1033309668.

The product of its digits is 72000, while the sum is 38.

Adding to 14341112255531 its reverse (13555221114341), we get a palindrome (27896333369872).

The spelling of 14341112255531 in words is "fourteen trillion, three hundred forty-one billion, one hundred twelve million, two hundred fifty-five thousand, five hundred thirty-one".