Base | Representation |
---|---|
bin | 1000010110010000000… |
… | …0110100001010001011 |
3 | 111201011121201010022122 |
4 | 2011210000310022023 |
5 | 4322201413343021 |
6 | 145514341441455 |
7 | 13234610443244 |
oct | 2054400641213 |
9 | 451147633278 |
10 | 143411856011 |
11 | 55903288056 |
12 | 2396441028b |
13 | 106a66a93c8 |
14 | 6d26803ccb |
15 | 3ae551bbab |
hex | 216403428b |
143411856011 has 2 divisors, whose sum is σ = 143411856012. Its totient is φ = 143411856010.
The previous prime is 143411855911. The next prime is 143411856017. The reversal of 143411856011 is 110658114341.
It is a strong prime.
It is an emirp because it is prime and its reverse (110658114341) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 143411856011 - 210 = 143411854987 is a prime.
It is not a weakly prime, because it can be changed into another prime (143411856017) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 71705928005 + 71705928006.
It is an arithmetic number, because the mean of its divisors is an integer number (71705928006).
Almost surely, 2143411856011 is an apocalyptic number.
143411856011 is a deficient number, since it is larger than the sum of its proper divisors (1).
143411856011 is an equidigital number, since it uses as much as digits as its factorization.
143411856011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 35.
The spelling of 143411856011 in words is "one hundred forty-three billion, four hundred eleven million, eight hundred fifty-six thousand, eleven".
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