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14341256118961 is a prime number
BaseRepresentation
bin1101000010110001010101…
…1110100000001010110001
31212210000021210111222021121
43100230111132200022301
53334431343031301321
650300140534022241
73010056460453222
oct320542536401261
955700253458247
1014341256118961
11462a102226772
1217375217a7981
138004b4147b65
14378198919249
1519d0b04b7441
hexd0b157a02b1

14341256118961 has 2 divisors, whose sum is σ = 14341256118962. Its totient is φ = 14341256118960.

The previous prime is 14341256118877. The next prime is 14341256119007. The reversal of 14341256118961 is 16981165214341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11354473729600 + 2986782389361 = 3369640^2 + 1728231^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14341256118961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14341256118899 and 14341256118908.

It is not a weakly prime, because it can be changed into another prime (14341256118361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170628059480 + 7170628059481.

It is an arithmetic number, because the mean of its divisors is an integer number (7170628059481).

Almost surely, 214341256118961 is an apocalyptic number.

It is an amenable number.

14341256118961 is a deficient number, since it is larger than the sum of its proper divisors (1).

14341256118961 is an equidigital number, since it uses as much as digits as its factorization.

14341256118961 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1244160, while the sum is 52.

The spelling of 14341256118961 in words is "fourteen trillion, three hundred forty-one billion, two hundred fifty-six million, one hundred eighteen thousand, nine hundred sixty-one".