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1434128550353 is a prime number
BaseRepresentation
bin10100110111101000101…
…110010000100111010001
312002002201212212210020022
4110313220232100213101
5141444043402102403
63014455103553225
7205420020354602
oct24675056204721
95062655783208
101434128550353
115032351a7304
121b1b3a8bb815
13a531241c375
144d5ab0abda9
1527489452d38
hex14de8b909d1

1434128550353 has 2 divisors, whose sum is σ = 1434128550354. Its totient is φ = 1434128550352.

The previous prime is 1434128550301. The next prime is 1434128550373. The reversal of 1434128550353 is 3530558214341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1433594339584 + 534210769 = 1197328^2 + 23113^2 .

It is an emirp because it is prime and its reverse (3530558214341) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1434128550353 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1434128550373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 717064275176 + 717064275177.

It is an arithmetic number, because the mean of its divisors is an integer number (717064275177).

Almost surely, 21434128550353 is an apocalyptic number.

It is an amenable number.

1434128550353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1434128550353 is an equidigital number, since it uses as much as digits as its factorization.

1434128550353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864000, while the sum is 44.

The spelling of 1434128550353 in words is "one trillion, four hundred thirty-four billion, one hundred twenty-eight million, five hundred fifty thousand, three hundred fifty-three".