14341350113 has 2 divisors, whose sum is σ = 14341350114. Its totient is φ = 14341350112.

The previous prime is 14341350097. The next prime is 14341350131. The reversal of 14341350113 is 31105314341.

Together with next prime (14341350131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12811523344 + 1529826769 = 113188^2 + 39113^2 .

It is a cyclic number.

It is not a de Polignac number, because 14341350113 - 2⁴ = 14341350097 is a prime.

It is a super-2 number, since 2×14341350113² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14341350143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7170675056 + 7170675057.

It is an arithmetic number, because the mean of its divisors is an integer number (7170675057).

Almost surely, 2^14341350113 is an apocalyptic number.

It is an amenable number.

14341350113 is a deficient number, since it is larger than the sum of its proper divisors (1).

14341350113 is an equidigital number, since it uses as much as digits as its factorization.

14341350113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 14341350113 its reverse (31105314341), we get a palindrome (45446664454).

The spelling of 14341350113 in words is "fourteen billion, three hundred forty-one million, three hundred fifty thousand, one hundred thirteen".