143414011122341 has 8 divisors (see below), whose sum is σ = 146912448946200. Its totient is φ = 139915598780160.

The previous prime is 143414011122329. The next prime is 143414011122401. The reversal of 143414011122341 is 143221110414341.

It can be written as a sum of positive squares in 4 ways, for example, as 20064755596900 + 123349255525441 = 4479370^2 + 11106271^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143414011122341 - 2¹⁰ = 143414011121317 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 143414011122298 and 143414011122307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143414011122301) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5279855 + ... + 17739923.

It is an arithmetic number, because the mean of its divisors is an integer number (18364056118275).

Almost surely, 2^{143414011122341} is an apocalyptic number.

It is an amenable number.

143414011122341 is a deficient number, since it is larger than the sum of its proper divisors (3498437823859).

143414011122341 is a wasteful number, since it uses less digits than its factorization.

143414011122341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12740839.

The product of its (nonzero) digits is 9216, while the sum is 32.

Adding to 143414011122341 its reverse (143221110414341), we get a palindrome (286635121536682).

The spelling of 143414011122341 in words is "one hundred forty-three trillion, four hundred fourteen billion, eleven million, one hundred twenty-two thousand, three hundred forty-one".