14342133124341 has 144 divisors (see below), whose sum is σ = 23761771488000. Its totient is φ = 8323747280640.

The previous prime is 14342133124327. The next prime is 14342133124351.

14342133124341 is a `hidden beast` number, since 1 + 4 + 3 + 4 + 213 + 3 + 1 + 2 + 434 + 1 = 666.

14342133124341 is nontrivially palindromic in base 10.

It is not a de Polignac number, because 14342133124341 - 2¹⁰ = 14342133123317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14342133124296 and 14342133124305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14342133124351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 510945855 + ... + 510973923.

It is an arithmetic number, because the mean of its divisors is an integer number (165012302000).

Almost surely, 2^{14342133124341} is an apocalyptic number.

14342133124341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14342133124341 is a deficient number, since it is larger than the sum of its proper divisors (9419638363659).

14342133124341 is a wasteful number, since it uses less digits than its factorization.

14342133124341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28360 (or 28346 counting only the distinct ones).

The product of its digits is 82944, while the sum is 36.

It can be divided in two parts, 1434213 and 3124341, that added together give a palindrome (4558554).

The spelling of 14342133124341 in words is "fourteen trillion, three hundred forty-two billion, one hundred thirty-three million, one hundred twenty-four thousand, three hundred forty-one".