Base | Representation |
---|---|
bin | 1101000010111000010101… |
… | …1010100110011000101101 |
3 | 1212210012010200100112101012 |
4 | 3100232011122212120231 |
5 | 3334444214320102140 |
6 | 50301051142355005 |
7 | 3010154143430060 |
oct | 320560532463055 |
9 | 55705120315335 |
10 | 14343134144045 |
11 | 462a986332813 |
12 | 173796672ba65 |
13 | 8007232563c5 |
14 | 3782d61028d7 |
15 | 19d1702d4265 |
hex | d0b856a662d |
14343134144045 has 16 divisors (see below), whose sum is σ = 20705877863040. Its totient is φ = 9317645037504.
The previous prime is 14343134144021. The next prime is 14343134144057. The reversal of 14343134144045 is 54044143134341.
It is a cyclic number.
It is not a de Polignac number, because 14343134144045 - 212 = 14343134139949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14343134143993 and 14343134144011.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10784310722 + ... + 10784312051.
It is an arithmetic number, because the mean of its divisors is an integer number (1294117366440).
Almost surely, 214343134144045 is an apocalyptic number.
It is an amenable number.
14343134144045 is a deficient number, since it is larger than the sum of its proper divisors (6362743718995).
14343134144045 is a wasteful number, since it uses less digits than its factorization.
14343134144045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21568622804.
The product of its (nonzero) digits is 552960, while the sum is 41.
Adding to 14343134144045 its reverse (54044143134341), we get a palindrome (68387277278386).
The spelling of 14343134144045 in words is "fourteen trillion, three hundred forty-three billion, one hundred thirty-four million, one hundred forty-four thousand, forty-five".
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