Base | Representation |
---|---|
bin | 1101000010111000010101… |
… | …1010100110011000010101 |
3 | 1212210012010200100112100022 |
4 | 3100232011122212120111 |
5 | 3334444214320102041 |
6 | 50301051142354525 |
7 | 3010154143430024 |
oct | 320560532463025 |
9 | 55705120315308 |
10 | 14343134144021 |
11 | 462a9863327a1 |
12 | 173796672ba45 |
13 | 8007232563a7 |
14 | 3782d61028bb |
15 | 19d1702d424b |
hex | d0b856a6615 |
14343134144021 has 2 divisors, whose sum is σ = 14343134144022. Its totient is φ = 14343134144020.
The previous prime is 14343134143999. The next prime is 14343134144057. The reversal of 14343134144021 is 12044143134341.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13573108588900 + 770025555121 = 3684170^2 + 877511^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14343134144021 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14343134144081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171567072010 + 7171567072011.
It is an arithmetic number, because the mean of its divisors is an integer number (7171567072011).
Almost surely, 214343134144021 is an apocalyptic number.
It is an amenable number.
14343134144021 is a deficient number, since it is larger than the sum of its proper divisors (1).
14343134144021 is an equidigital number, since it uses as much as digits as its factorization.
14343134144021 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 14343134144021 its reverse (12044143134341), we get a palindrome (26387277278362).
The spelling of 14343134144021 in words is "fourteen trillion, three hundred forty-three billion, one hundred thirty-four million, one hundred forty-four thousand, twenty-one".
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