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14343254550217 is a prime number
BaseRepresentation
bin1101000010111000110010…
…0101111010011011001001
31212210012110001220210121001
43100232030211322123021
53334444441131101332
650301111123215001
73010160135032345
oct320561445723311
955705401823531
1014343254550217
11462aa382a174a
12173799ab17461
13800742193168
143783080c6625
1519d17ab6a0e7
hexd0b8c97a6c9

14343254550217 has 2 divisors, whose sum is σ = 14343254550218. Its totient is φ = 14343254550216.

The previous prime is 14343254550167. The next prime is 14343254550259. The reversal of 14343254550217 is 71205545234341.

14343254550217 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9717503178681 + 4625751371536 = 3117291^2 + 2150756^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14343254550217 is a prime.

It is not a weakly prime, because it can be changed into another prime (14343254550517) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171627275108 + 7171627275109.

It is an arithmetic number, because the mean of its divisors is an integer number (7171627275109).

Almost surely, 214343254550217 is an apocalyptic number.

It is an amenable number.

14343254550217 is a deficient number, since it is larger than the sum of its proper divisors (1).

14343254550217 is an equidigital number, since it uses as much as digits as its factorization.

14343254550217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016000, while the sum is 46.

Adding to 14343254550217 its reverse (71205545234341), we get a palindrome (85548799784558).

The spelling of 14343254550217 in words is "fourteen trillion, three hundred forty-three billion, two hundred fifty-four million, five hundred fifty thousand, two hundred seventeen".