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14343301057 is a prime number
BaseRepresentation
bin11010101101110110…
…10110011111000001
31101000121110012002111
431112323112133001
5213333341113212
610331134415321
71015304022151
oct152673263701
941017405074
1014343301057
1160a0468418
122943661541
13147778abb7
149a0d1c761
1558e346ea7
hex356ed67c1

14343301057 has 2 divisors, whose sum is σ = 14343301058. Its totient is φ = 14343301056.

The previous prime is 14343300991. The next prime is 14343301073. The reversal of 14343301057 is 75010334341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12428013361 + 1915287696 = 111481^2 + 43764^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14343301057 is a prime.

It is not a weakly prime, because it can be changed into another prime (14343301157) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7171650528 + 7171650529.

It is an arithmetic number, because the mean of its divisors is an integer number (7171650529).

Almost surely, 214343301057 is an apocalyptic number.

It is an amenable number.

14343301057 is a deficient number, since it is larger than the sum of its proper divisors (1).

14343301057 is an equidigital number, since it uses as much as digits as its factorization.

14343301057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15120, while the sum is 31.

Adding to 14343301057 its reverse (75010334341), we get a palindrome (89353635398).

The spelling of 14343301057 in words is "fourteen billion, three hundred forty-three million, three hundred one thousand, fifty-seven".